JEE Main 27 June 2022 Shift 2 Solved Paper

Section: Physics

Question : 48 of 90

Marks: +1, -0

Given below are two statements :
Statement I : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E .E1) to higher energy orbit (E2), is given as hf=E1−E2
Statement II : The jumping of electron from higher energy orbit (E2) to lower energy orbit (E1) is associated with frequency of radiation given as f=(E2−E1)∕h
This condition is Bohr's frequency condition.
In the light of the above statements, choose the correct answer from the options given below :

[27-Jun-2022-Shift-2]

Both Statement I and Statement II are true.
Both Statement I and Statement II are false.
Statement I is correct but Statement II is false.
Statement I is incorrect but Statement II is true.

Validate

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