The equation of a particle executing simple harmonic motion is given by x=\sin \pi(t+\frac{1}{3}) m. At t=1 {\s}, the speed of particle will be (Given : \pi=3.14 ) [27-Jun-2022-Shift-2]

JEE Main 27 June 2022 Shift 2 Solved Paper

Section: Physics

Question : 40 of 90

Marks: +1, -0

The equation of a particle executing simple harmonic motion is given by x=sin‌π(t+‌

)‌m. At t=1s, the speed of particle will be
(Given : π=3.14 )

[27-Jun-2022-Shift-2]

Go to Question:

Prev Question

Next Question