JEE Main 27 June 2022 Shift 2 Solved Paper
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Question : 28 of 90
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Let y = y ( x ) be the solution of the differential equation ( 1 − x 2 ) d y = ( x y + ( x 3 + 2 ) √ 1 − x 2 ) d x , − 1 < x < 1 , and y ( 0 ) = 0 . If
√ 1 − x 2 y ( x ) d x = k , then k − 1 is equal to____
[27-Jun-2022-Shift-2]
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