JEE Main 27 June 2022 Shift 2 Solved Paper

Section: Mathematics
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Question : 28 of 90
 
Marks: +1, -0
Let y=y(x) be the solution of the differential equation (1−x2)dy=(xy+(x3+2)√1−x2)dx,−1<x<1, and y(0)=0. If
‌
1
2
∫
‌
−1
2
√1−x2y(x)dx
=k
, then k−1 is equal to____
[27-Jun-2022-Shift-2]
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