Let \alpha, \beta be the roots of the equation x^2-4 \lambda x+5=0 and \alpha, \gamma be the roots of the equation x^2-(3 \sqrt{2}+2 \sqrt{3}) x+7+3 \lambda \sqrt{3}=0, \lambda>0. If \beta+\gamma=3 \sqrt{2}, then (\alpha+2 \beta+\gamma)^2 is equal to___ [27-Jun-2022-Shift-2]

JEE Main 27 June 2022 Shift 2 Solved Paper

Section: Mathematics

Question : 22 of 90

Marks: +1, -0

Let α,β be the roots of the equation x2−4λx+5=0 and α,γ be the roots of the equation x2−(3√2+2√3)x+7+3λ√3=0,λ>0. If β+γ=3√2, then (α+2β+γ)2 is equal to___

[27-Jun-2022-Shift-2]

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