Home Back

JEE Main 27 June 2022 Shift 2 Solved Paper

Section: Mathematics
© examsiri.com
Question : 2 of 90
 
Marks: +1, -0
Let f(x)=|
a−10
axa−1
ax2axa
|,a∈R. Then the sum of the squares of all the values of a, for which 2f′(10)−f′(5)+100=0, is
[27-Jun-2022-Shift-2]
Validate
Go to Question:
Prev Question
Next Question