JEE Main 27 June 2022 Shift 1 Solved Paper

Section: Mathematics

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Question : 9 of 90

Marks: +1, -0

If ∫‌

(x2+1)ex

(x+1)2

dx=f(x)ex+C, where C is a constant, then ‌

d3f

dx3

at x=1 is equal to :

[27-Jun-2022-Shift-1]

−‌
3
4
‌
3
4
−‌
3
2
‌
3
2

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