JEE Main 27 June 2022 Shift 1 Solved Paper

Let atomic weight of A=x
and atomic weight of B=y
∴ Molar mass of A2B=2x+y
and molar mass of AB3=x+3y
Now, weight of 0.15 moles of A2B=(2x+y)0.15
and weight of 0.15 moles of AB3=(x+3y)0.15
Given, weight of 0.15 moles of A2B and AB3 are equal.
∴(2x+y)0.15=(x+3y)0.15
⇒x=2y
⇒‌

x

y

=2
∴ Atomic weight of A is 2 times of atomic weight of B.