JEE Main 27 June 2022 Shift 1 Solved Paper

For a head on elastic collision
v2=‌

mu1

m+5m

+‌

mu1

m+5m

=‌

2u1

6

‌ or ‌‌

u1

3

Initial kinetic energy of first mass =‌

1

2

mu12
Final kinetic energy of second mass
=‌

1

2

×5m(‌

u1

3

)2
=‌

5

9

(‌

1

2

mu12)
⇒ kinetic energy transferred =55% of initial kinetic energy of first colliding mass