JEE Main 27 June 2022 Shift 1 Solved Paper

Section: Physics

Question : 31 of 90

Marks: +1, -0

A projectile is launched at an angle ' α ' with the horizontal with a velocity 20ms−1. After 10s, its inclination with horizontal is ' β '. The value of tan‌β will be : (g=10ms−2).

[27-Jun-2022-Shift-1]

tan‌α+5‌sec‌α
tan‌α−5‌sec‌α
2‌tan‌α−5‌sec‌α
2‌tan‌α+5‌sec‌α

Validate

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