Let {N} be the set of natural numbers and a relation{R} on {N} be defined by {R}=\{({x}, {y}) \\in {N} \\times{N}: {x}^{3}-3 {x}^{2} {y} -{xy}^{2}+3 {y}^{3}=0\}Then the relation {R} is : [27 Jul 2021 Shift 2]

Correct Answer is : reflexive but neither symmetric nor transitive

symmetric but neither reflexive nor transitive

reflexive but neither symmetric nor transitive

reflexive and symmetric, but not transitive

JEE Main 27 July 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 75 of 90

Marks: +1, -0

Let N be the set of natural numbers and a relationR on N be defined by R={(x,y)∈N×N:x3−3x2y −xy2+3y3=0}Then the relation R is :

[27 Jul 2021 Shift 2]

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