JEE Main 27 July 2021 Shift 2 Solved Paper

The Kα X-ray of molybdenum has wavelength0.071nm. If the energy of a molybdenum atoms with a K electron knocked out is 27.5keV, the energy of this atom when an L electron is knocked out will be ______ keV. (Round off to the nearest integer)
[h=4.14×10−15eVs,c=3×108ms−1]