JEE Main 27 July 2021 Shift 1 Solved Paper

Section: Mathematics

© examsiri.com

Question : 72 of 90

Marks: +1, -0

Let f:(−

π

4

,

π

4

)→R be defined as

f(x)={

(1+|sin‌x|)

3a

|sin‌x|

,

−

π

4

<x<0

b

,

x=0

ecot‌4‌x∕cot‌2‌x

,

0<x<

π

4

If f is continuous at x=0, then the value of 6a+b2is equal to:

[27 Jul 2021 Shift 1]

1−e
e -1
1+e
e

Go to Question:

Prev Question

Next Question