JEE Main 27 July 2021 Shift 1 Solved Paper

Section: Chemistry

Question : 58 of 90

Marks: +1, -0

For water at 100°C and 1 bar,
Δvap H−Δvap U= ───×102J mol−1.
(Round off to the Nearest Integer)
[Use : R=8.31Jmol−1K−1]
[Assume volume of H2O(l) is much smaller than volume of H2O(g). Assume H2O(g) treated as an ideal gas]

[27 Jul 2021 Shift 1]

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