Two identical tennis balls each having mass 'm' and charge ' q ' are suspended from a fixed point by threads of length . What is the equilibrium separation when each thread makes a small angle with the vertical ? [27 Jul 2021 Shift 1]l '. What is the equilibrium separation when each thread makes a small angle ' \θ' with the vertical ? [27 Jul 2021 Shift 1] \\theta' with the vertical ? [27 Jul 2021 Shift 1]l '. What is the equilibrium separation when each thread makes a small angle ' \θ' with the vertical ? [27 Jul 2021 Shift 1]

Correct Answer is : x=(q2l2πε0mg)13

x=({q^{2} l}/{2 \\pi\\epsilon_{0} m g})^{\frac{1}{2}}

x=({q^{2} l}/{2 \\pi\\epsilon_{0} m g})^{\frac{1}{3}}

x=({q^{2} l^2}/{2 \\pi\\epsilon_{0} m ^2g})^{\frac{1}{2}}

x=({q^{2} l^2}/{2 \\pi\\epsilon_{0} m ^2g^2})^{\frac{1}{2}}

JEE Main 27 July 2021 Shift 1 Solved Paper

Section: Physics

Question : 18 of 90

Marks: +1, -0

Two identical tennis balls each having mass 'm' and charge ' q ' are suspended from a fixed point by threads of length ′l′. What is the equilibrium separation when each thread makes a small angle ′θ′ with the vertical ?

[27 Jul 2021 Shift 1]

x=(
q2l
2πε0mg
)
1
2
x=(
q2l
2πε0mg
)
1
3
x=(
q2l2
2πε0m2g
)
1
2
x=(
q2l2
2πε0m2g2
)
1
2

Validate

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