Identify B formed in the reaction. {\Cl}- ( {\CH}_2) _4- {\Cl} \stackrel{\text{ excess }{─\xrightarrow {\NH}_3} {\A} \stackrel{ {\NaOH}{─\xrightarrow} {\B}+ {\H}_2 {\O}+ {\NaCl} [27-Jan-2024 Shift 2]

Correct Answer is : H2N−(CH2)4−NH2

{\H}_2 {\N}- ( {\CH}_2) _4- {\NH}_2

{ \Cl}↖{} {{\N}}^{+} \stackrel{ }{\H}_3- ( {\CH}_2) _4- \stackrel{+}{ \N} {\H↖{}}_3 {\Cl}^{-}

JEE Main 27-Jan-2024 Shift 2 Solved Paper

Section: Chemistry

Question : 75 of 90

Marks: +1, -0

Identify B formed in the reaction.

Cl−(CH2)4−Cl‌

‌ excess ‌NH3

────────▶

‌A‌

NaOH

────────▶

‌B+H2O+NaCl

[27-Jan-2024 Shift 2]

Go to Question:

Prev Question

Next Question