JEE Main 27-Jan-2024 Shift 2 Solved Paper

Section: Mathematics

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Question : 15 of 90

Marks: +1, -0

If 2tan2θ−5 secθ=1 has exactly 7 solutions in the interval [0,‌

nπ

2

], for the least value of n∈N then

n

∑

k=1

‌

k

2k

is equal to :

[27-Jan-2024 Shift 2]

‌
1
215
(214−14)
‌
1
214
(215−15)
1−‌
15
213
‌
1
213
(214−15)

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