Two discs have moments of inertia \I_{1} and \I_{2} about their respective axes perpendicular to the plane and passing through the centre. They are rotating with angular speeds, \\omega_{1} and \\omega_{2} respectively and are brought into contact face to face with their axes of rotation co-axial. The loss in kinetic energy of the system in the process is given by [27 Aug 2021 Shift 2]

Correct Answer is : I1I22(I1+I2)(ω1−ω2)2

{\I_{1} \I_{2}}/{(\I_{1}+\I_{2})}(\\omega_{1}-\\omega_{2})^{2}

{(\I_{1}-\I_{2})^{2} \\omega_{1} \\omega_{2}}/{2(\I_{1}+\I_{2})}

{\I_{1} \I_{2}}/{2(\I_{1}+\I_{2})}(\\omega_{1}-\\omega_{2})^{2}

{(\\omega_{1}-\\omega_{2})^{2}}/{2(\I_{1}+\I_{2})}

JEE Main 27-Aug-2021 Shift 2 Solved Paper

Section: Physics

Question : 5 of 90

Marks: +1, -0

Two discs have moments of inertia I1 and I2 about their respective axes perpendicular to the plane and passing through the centre. They are rotating with angular speeds, ω1 and ω2 respectively and are brought into contact face to face with their axes of rotation co-axial. The loss in kinetic energy of the system in the process is given by

[27 Aug 2021 Shift 2]

I1I2
(I1+I2)
(ω1−ω2)2
(I1−I2)2ω1ω2
2(I1+I2)
I1I2
2(I1+I2)
(ω1−ω2)2
(ω1−ω2)2
2(I1+I2)

Validate

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