JEE Main 27-Aug-2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 64 of 90

Marks: +1, -0

If (sin−1x)2−(cos−1x)2=a,0<x<1,a≠0, then the value of 2x2−1 is

[27 Aug 2021 Shift 1]

cos(
4a
π
)
sin(
2a
π
)
cos(
2a
π
)
sin(
4a
π
)

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