{\Cu}( {\s})+ {\Sn}^{2+}(0.001 {\M}) \to {\Cu}^{2+}(0.01 {\M})+ {\Sn}( {\s}) The Gibbs free energy change for the above reaction at 298 {\K} is x \times 10^{-1} {\kJ} {\mol}^{-1}. The value of {\x} is ______ [nearest integer] [Given : E_{C u^{2+} \/ C u}^{\Theta}=0.34 V ; E_{S n^{2+} \/ S n}^{\Theta}=-0.14 V ; {\F}=96500 {\C} {\mol}^{-1} ] [26-Jun-2022-Shift-2]

JEE Main 26 June 2022 Shift 2 Solved Paper

Section: Chemistry

Question : 87 of 90

Marks: +1, -0

Cu(s)+Sn2+(0.001M)→Cu2+(0.01M)+Sn(s)
The Gibbs free energy change for the above reaction at 298K is x×10−1‌kJ‌mol−1. The value of x is ______ [nearest integer]
[Given : ECu2+∕CuΘ=0.34V;ESn2+∕SnΘ=−0.14V;F=96500Cmol−1 ]

[26-Jun-2022-Shift-2]

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