The stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 6630 \stackrel{o}{A} is 0.42 {\V}. If the threshold frequency is x \times 10^{13} \/ {\s}, where {\x} is____ (nearest integer). (Given, speed light =3 \times 10^8 {\m} \/ {\s}, Planck's constant =6.63 \times 10^{-34} {\Js} ) [26-Jun-2022-Shift-2]

JEE Main 26 June 2022 Shift 2 Solved Paper

Section: Physics

Question : 60 of 90

Marks: +1, -0

The stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 6630

is 0.42V. If the threshold frequency is x×1013∕s, where x is____ (nearest integer).
(Given, speed light =3×108m∕s, Planck's constant =6.63×10−34‌Js )

[26-Jun-2022-Shift-2]

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