JEE Main 26 Feb 2021 Shift 2 Solved Paper

(A) Sodium carbonate is manufactured by Solvay process ⇒ (iv) of List-ll.
Solvay process's reactions are as follows
In Solvay's process, first ammonia (NH3) reacts with CO2 and H2O to give ammonium bicarbonate (NH4HCO3).
This bicarbonate react with NaCl to give sodium bicarbonate (NaHCO3) along with ammonium chloride (NH4Cl).
At last, NaHCO3 is heated to form sodium carbonate as major product.
NH3+CO2+H2O⟶NH4HCO3
NH4HCO3+

NaCl

(Brine)

⟶NaHCO3↓+NH4Cl
‌2NaHCO3⟶∆2⟶

Na2CO3

Sodium‌carbonate

+CO2+H2O
(B) Titanium is purified by van-Arkel method ⇒ (iii) of List-II
van-Arkel method
Crude titanium

780K

⟶

I2

Til 4(g)‌

1800K

⟶

‌

Ti

(Pure)

+2I2
(C) Chlorine is manufactured by Deacon process ⇒ (i) of List-II.
Deacon process
4HCl(g)+

O2(g)

[Air]

CuCl2‌ (catalyst) ‌

───────▶

723K

2Cl2

Chlorine‌gas

+2H2O(g)
(D) Sodium hydroxide is manufactured by Castner-Kellner cell ⇒ (ii) of List-II.
Castner-Kellner cell reaction
Electrolyte used is brine, saturated NaCl solution. Cathode (Hg) :
Na++e−⟶Na

Hg

⟶

Na∕Hg
Anode (carbon) : Cl−+e−⟶‌

1

2

Cl2↑
2Na∕Hg+2H2O⟶

2NaOH

Sodium‌hydroxide

+2Hg+H2↑