JEE Main 26 Feb 2021 Shift 2 Solved Paper

According to given data;
Initial speed of scooter, u1=0ms−1
and final speed, v2=0ms−1
By using first equation of motion,
‌v1‌‌=u+a1t1
‌⇒‌v1‌‌=a1t1. . . (i)
and for second case,
v2‌‌=v1−a2t2
0‌‌=v1−a2t2
v1‌‌=a2t2 . . . (ii)
On dividing Eq. (i) by Eq. (ii), we get
‌v1∕v1‌‌=1=‌

a1t1

a2t2

⇒‌a2t2‌‌=a1t1
⇒‌t1∕t2‌‌=a2∕a1