An alternating current is given by the equation i=i_{1} \sin \omega t+i_{2} \cos \omega t. The rms current will be [26 Feb 2021 Shift 1]

Correct Answer is : 1√2(i12+i22)1∕2

\frac{1}\sqrt{2}(i_{1}^{2}+i_{2}^{2})^{1 \/ 2}

\frac{1}\sqrt{2}(i_{1}+i_{2})^{2}

\frac{1}{2}(i_{1}^{2}+i_{2}^{2})^{1 \/ 2}

JEE Main 26 Feb 2021 Shift 1 Solved Paper

Section: Physics

Question : 7 of 90

Marks: +1, -0

An alternating current is given by the equation i=i1‌sin‌ω‌t+i2‌cos‌ω‌t. The rms current will be

[26 Feb 2021 Shift 1]

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