JEE Main 26 Feb 2021 Shift 1 Solved Paper

Given, mass of solid sphere =m
Radius of solid sphere =a
Side of square =b
Let I‌net ‌ be the net moment of inertia of system.
Moment of inertia of sphere, Is=‌

2

5

ma2
Axis of rotation is BC. ∴ Moment of inertia of any body at distance,
(∵d=b)
d‌‌=md2=mb2
∴‌‌I‌net ‌‌‌=4(‌

2

5

ma2)+2(mb2)
∴‌‌‌net ‌‌‌=4(‌

2

5

ma2)+2(mb2)
⇒‌‌I‌net ‌‌‌=‌

8

5

ma2+2mb2