Find the gravitational force of attraction between the ring and sphere as shown in the figure, where the plane of the ring is perpendicular to the line joining the centres. If \sqrt{8} R is the distance between the centres of a ring (of mass m ) and a sphere (of mass M ), where both have equal radius R. [26 Feb 2021 Shift 1]

Correct Answer is : √827⋅GmMR2

\frac\sqrt{8}{9} \cdot \frac{G m M}{R}

\frac{2 \sqrt{2}{3} \cdot \frac{G M m}{R^{2}}

\frac{1}{3 \sqrt{8} \cdot \frac{G M m}{R^{2}}

\frac\sqrt{8}{27} \cdot \frac{G m M}{R^{2}}

JEE Main 26 Feb 2021 Shift 1 Solved Paper

Section: Physics

Question : 1 of 90

Marks: +1, -0

Find the gravitational force of attraction between the ring and sphere as shown in the figure, where the plane of the ring is perpendicular to the line joining the centres. If √8R is the distance between the centres of a ring (of mass m ) and a sphere (of mass M ), where both have equal radius R.

[26 Feb 2021 Shift 1]

‌
√8
9
⋅‌
GmM
R
‌
2√2
3
⋅‌
GMm
R2
‌
1
3√8
⋅‌
GMm
R2
‌
√8
27
⋅‌
GmM
R2

Validate

Go to Question:

Next Question