JEE Main 26-Aug-2021 Shift 2 Solved Paper

Section: Mathematics

Question : 66 of 90

Marks: +1, -0

Let y(x) be the solution of the differential equation 2x2dy+(ey−2x)dx=0,x>0. If y(e)=1, then y(1) is equal to

[26 Aug 2021 Shift 2]

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