JEE Main 26-Aug-2021 Shift 2 Solved Paper

Equation for light beam is given as
E=800‌sin(ωt−

x

C

)
Here, c is speed of light.
Comparing with standard equation, we get
E0=800Vm−1
As we know, the magnitude of magnetic field is given as
E0=B0C
⇒800=B0×3×108
⇒B0=

800

3×108

T
Maximum magnetic force exerted on electron will be
Fmax=ev‌B0
=(1.6×10−19)×(3×107)×

800

3×108

(Given, v=3×107ms−1 )
Fmax=12.8×10−18‌N or 1.28×10−17