100 {\mL} of {\Na}_{3} {\PO}_{4} solution contains 3.45 {\g} of sodium. The molarity of the solution is ...... \times10^{-2} {\mol} {\L}^{-1}. (Nearest integer) [ Atomic masses -{\Na}=23.0 {\u}, {\O}=16.0 {\u},, {\P}=31.0 {\u}] [26 Aug 2021 Shift 2]

JEE Main 26-Aug-2021 Shift 2 Solved Paper

Section: Chemistry

Question : 56 of 90

Marks: +1, -0

100‌mL of Na3PO4 solution contains 3.45g of sodium. The molarity of the solution is ...... ×10−2‌mol‌L−1. (Nearest integer)
[ Atomic masses −Na=23.0u,O=16.0u,, P=31.0u]

[26 Aug 2021 Shift 2]

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