JEE Main 26-Aug-2021 Shift 2 Solved Paper

Given, radius of circular coil, r = 8.0 cm = 0.08 m
Number of turns, N = 20
Angular speed of coil, ω=50‌rad‌s−1
Magnetic field, B=3.0×10−2T
The maximum emf induced in a coil can be expressed as
ε=ω‌NBA
Here, A is the area of coil.
ε=NB‌ω(πr2)
Substituting the given values, we get
ε=20×3.0×10−2×50×π×(0.08)2
=60.3×10−2V
≃60×10−2V