A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant \K_{1} and \K_{2} of same area \A / 2 and thickness d / 2 are inserted in the space between the plates. The capacitanceof the capacitor will be given by [26 Aug 2021 Shift 2]

Correct Answer is : ε0Ad(12+K1K2K1+K2)

{\\epsilon_{0} \A}/{d}(\frac{1}{2}+{\K_{1} \K_{2}}/{\K_{1}+\K_{2}})

{\\epsilon_{0} \A}/{d}(\frac{1}{2}+{\K_{1} \K_{2}}/{2(\K_{1}+\K_{2})})

{\\epsilon_{0} \A}/{d}(\frac{1}{2}+{\K_{1}+\K_{2}}/{\K_{1} \K_{2}})

{\\epsilon_{0} \A}/{d}(\frac{1}{2}+{2(\K_{1}+\K_{2})}/{\K_{1} \K_{2}})

JEE Main 26-Aug-2021 Shift 2 Solved Paper

Section: Physics

Question : 10 of 90

Marks: +1, -0

A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K1 and K2 of same area

and thickness

are inserted in the space between the plates. The capacitanceof the capacitor will be given by

[26 Aug 2021 Shift 2]

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