JEE Main 26-Aug-2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 67 of 90

Marks: +1, -0

Let‌f(x)=cos(2tan−1‌sin(cot−1√

1−x

x

)),0<x<1.

Then,

[26 Aug 2021 Shift 1]

(1−x)2f′(x)−2(f(x))2=0
(1+x)2f′(x)+2(f(x))2=0
(1−x)2f′(x)+2(f(x))2=0
(1+x)2f′(x)−2f(x))2=0

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