JEE Main 25 June 2022 Shift 2 Solved Paper

Moment of Inertia (M.I.) of four bodies having same mass 'M' and radius ' 2R′ are as follows:
I1= M.I. of solid sphere about its diameter
I2= M.I. of solid cylinder about its axis
I3= M.I. of solid circular disc about its diameter
I4= M.I. of thin circular ring about its diameter
If 2(I2+I3)+I4=x.I1, then the value of x will be