A disc with a flat small bottom beaker placed on it at a distance {\R} from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity \omega. The coefficient of static friction between the bottom of the beaker and the surface of the disc is \mu. The beaker will revolve with the disc if : [25-Jun-2022-Shift-2]

R \leq \frac{\mu g}{2 \omega^2}

R \geq \frac{\mu g}{2 \omega^2}

JEE Main 25 June 2022 Shift 2 Solved Paper

Section: Physics

Question : 33 of 90

Marks: +1, -0

A disc with a flat small bottom beaker placed on it at a distance R from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity ω. The coefficient of static friction between the bottom of the beaker and the surface of the disc is µ. The beaker will revolve with the disc if :

[25-Jun-2022-Shift-2]

R≤‌
µg
2ω2
R≤‌
µg
ω2
R≥‌
µg
2ω2
R≥‌
µg
ω2

Validate

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