JEE Main 25 June 2022 Shift 2 Solved Paper

Section: Mathematics
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Question : 2 of 90
 
Marks: +1, -0
Let a,b∈R be such that the equation ax2−2bx+15=0 has a repeated root α. If α and β are the roots of the equation x2−2bx+21=0, then α2+β2 is equal to :
[25-Jun-2022-Shift-2]
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