JEE Main 25 June 2022 Shift 2 Solved Paper
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Question : 13 of 90
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If y = y ( x ) is the solution of the differential equation 2 x 2
− 2 x y + 3 y 2 = 0 such that y ( e ) =
, then y ( 1 ) is equal to
[25-Jun-2022-Shift-2]
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