JEE Main 25 June 2022 Shift 1 Solved Paper

Section: Mathematics

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Question : 8 of 90

Marks: +1, -0

If ‌

1

2⋅310

+‌

1

22⋅39

+...+‌

1

210⋅3

=‌

K

210⋅310

, then the remainder when K is divided by 6 is :

[25-Jun-2022-Shift-1]

1
2
3
5

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