JEE Main 25 June 2022 Shift 1 Solved Paper

Section: Mathematics

Question : 24 of 90

Marks: +1, -0

Let the abscissae of the two points P and Q be the roots of 2x2−rx+p=0 and the ordinates of P and Q be the roots of x2−sx−q=0. If the equation of the circle described on PQ as diameter is 2(x2+y2)−11x−14y−22=0, then 2r+s−2q+p is equal to

[25-Jun-2022-Shift-1]

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