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Question : 14 of 90
Marks:
+1,
-0
Solution:
cos2α+cos2β+cos2γ=1⇒cos2α=‌⇒cos‌α=‌=‌(++widehat‌k),λ>0‌‌| (++widehat‌k)⋅(3+4) |
| √32+42 |
=7⇒‌(3+4)=7×5∴λ=5√3=5(++widehat‌k)Let
=p+q+r‌widehat‌k⋅=0 and
[b]=0⇒p+q+r=0 &||=0⇒q=r=−2r+r+r‌widehat‌k=r(−2++widehat‌k)‌ Now ‌||=||5√3=|r|√b⇒|r|=‌⇒‌ Projection of ‌‌ on ‌3+4=|‌|=|r|‌=|‌|‌ Projection ‌=‌×‌=√2∴B is correct.
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