JEE Main 25 July 2021 Shift 2 Solved Paper

Section: Physics

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Question : 3 of 90

Marks: +1, -0

A force

→

F

=(40

^

i

+10

^

j

)N acts on a body of mass5kg. If the body starts from rest, its position vector

→

r

at time t=10s, will be :

[25 Jul 2021 Shift 2]

(100
^
i
+400
^
j
)m
(100
^
i
+100
^
j
)m
(400
^
i
+100
^
j
)m
(400
^
i
+400
^
j
)m

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