JEE Main 25 July 2021 Shift 2 Solved Paper

From the given data, the amount of energy required to break the nucleus of aluminium ‌1327Al is _____ x×10−3J
Mass of neutron =1.00866u
Mass of proton =1.00726u
Mass of Aluminium nucleus =27.18846u
(Assume 1 u corresponds to x J of energy)
(Round off to the nearest integer)