The instantaneous velocity of a particle moving in a straight line is given as v=\\alphat+\\betat^{2}, where \alpha and \beta are constants. The distance travelled by the particle between 1 {s} and 2 {s} is : [25 Jul 2021 Shift 2]

\frac{3}{2} \\alpha+\frac{7}{3} \\beta

\frac{\\alpha}{2}+\frac{\\beta}{3}

\frac{3}{2} \\alpha+\frac{7}{2} \\beta

JEE Main 25 July 2021 Shift 2 Solved Paper

Section: Physics

Question : 17 of 90

Marks: +1, -0

The instantaneous velocity of a particle moving in a straight line is given as v=αt+βt2, where alpha and beta are constants. The distance travelled by the particle between 1s and 2s is :

[25 Jul 2021 Shift 2]

3α+7β
3
2
α+
7
3
β
α
2
+
β
3
3
2
α+
7
2
β

Validate

Go to Question:

Prev Question

Next Question