JEE Main 25 July 2021 Shift 1 Solved Paper

Section: Chemistry

Question : 36 of 90

Marks: +1, -0

At 298.2K the relationship between enthalpy of bond dissociation (in kJmol−1 ) for hydrogen (EH) and its isotope, deuterium (ED), is best described by:

[25 Jul 2021 Shift 1]

EH=
1
2
ED
EH=ED
EH≃ED−7.5
EH=2ED

Validate

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