JEE Main 25 July 2021 Shift 1 Solved Paper
© examsiri.com
Question : 30 of 90
Marks:
+1,
-0
A particle of mass 'm' is moving in time 't' on a trajectory given by
= 10 α t 2
+ 5 β ( t − 5 )
Where α and β are dimensional constants.
The angular momentum of the particle becomes the same as it was for t = 0 at time t = ______seconds.
Where α and β are dimensional constants.
The angular momentum of the particle becomes the same as it was for t = 0 at time t = ______seconds.
[25 Jul 2021 Shift 1]
- Your Answer:
Go to Question: