What should be the order of arrangement of de-Broglie wavelength of electron (\\lambda_{{e}}), an \\alpha-particle (\\lambda_{\\alpha}) and proton (\\lambda_{{p}}) given that all have the same kinetic energy ? [25 Jul 2021 Shift 1]

Correct Answer is : λe>λp>λα

\\lambda_{{e}}=\\lambda_{{p}}=\\lambda_{\\alpha}

\\lambda_{{e}}>\\lambda_{{p}}>\\lambda_{\\alpha}

\\lambda_{{e}}=\\lambda_{{p}}>\\lambda_{\\alpha}

JEE Main 25 July 2021 Shift 1 Solved Paper

Section: Physics

Question : 3 of 90

Marks: +1, -0

What should be the order of arrangement of de-Broglie wavelength of electron (λe), an α-particle (λα) and proton (λp) given that all have the same kinetic energy ?

[25 Jul 2021 Shift 1]

λe=λp=λα
λe<λp<λα
λe>λp>λα
λe=λp>λα

Validate

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