A linearly polarized electromagnetic wave in vacuum is\mathrm{E}=3.1 \cos \left[(1.8) \mathrm{z}-\left(5.4 \times 10^{6}\right) \mathrm{t}\right] \hat{\mathrm{i}} \mathrm{N} / \mathrm{C}is incident normally on a perfectly reflecting wall at \mathrm{z}=\mathrm{a}. Choose the correct option [25 Jul 2021 Shift 1]

Correct Answer is : The reflected wave will be 3.1cos[(1.8)z+(5.4×106)t]^iN∕C

The frequency of electromagnetic wave is 54 \\times10^{4} {Hz}

The transmitted wave will be 3.1 \cos [(1.8) {z}-(5.4 \\times10^{6}) {t}] {{i}}^{\^} {N} \/ {C}

The reflected wave will be 3.1 \cos [(1.8) {z}+(5.4 \\times10^{6}) {t}] {{i}}^{\^} {N} \/ {C}

JEE Main 25 July 2021 Shift 1 Solved Paper

Section: Physics

Question : 16 of 90

Marks: +1, -0

A linearly polarized electromagnetic wave in vacuum ismathrm‌E=3.1‌cos‌left[(1.8)‌mathrm‌z−left(5.4‌times‌106‌right)‌mathrm‌t‌right]‌hat‌mathrm‌i‌mathrm‌

mathrm

‌Cis incident normally on a perfectly reflecting wall at mathrm‌z=mathrm‌a. Choose the correct option

[25 Jul 2021 Shift 1]

The wavelength is 5.4m
The frequency of electromagnetic wave is 54×104Hz
The transmitted wave will be 3.1‌cos[(1.8)z−(5.4×106)t]‌
^
i
‌N∕C
The reflected wave will be 3.1‌cos[(1.8)z+(5.4×106)t]‌
^
i
‌N∕C

Validate

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