JEE Main 25 Feb 2021 Shift 2 Solved Paper

Xe (sp3d2-hybridised)
Geometry : Octahedral
Shape : Square planar
It has four equivalent Xe−F bonds in the same plane.Si ( sp3-hybridised)
Geometry and shape : Tetrahedral
It has four equivalent Si−F bonds. S(sp3d-hybridised )
Geometry: Trigonal bipyramidal
Shape : see-saw
Axial S−F bonds are longer than equatorial bonds.B (sp ‌3-hybridised)
Geometry and shape : Tetrahedral
It has four equivalent B−F bonds.
Hence, among given species only SF4 has unequal bond lengt