The peak electric field produced by the radiation coming from the 8 {W} bulb at a distance of 10 {m} is \frac{x}{10} \sqrt{\frac{\mu_{0} c}{\pi}} { {V}}/{ {m}}. The efficiency of the bulb is 10 \% and it is a point source. The value of x is ............ . [25 Feb 2021 Shift 2]

JEE Main 25 Feb 2021 Shift 2 Solved Paper

Section: Physics

Question : 28 of 90

Marks: +1, -0

The peak electric field produced by the radiation coming from the 8W bulb at a distance of 10m is ‌

√‌

µ0c

‌

. The efficiency of the bulb is 10% and it is a point source. The value of x is ............ .

[25 Feb 2021 Shift 2]

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