JEE Main 25 Feb 2021 Shift 1 Solved Paper

In the given circuit of potentiometer, the potential difference E across AB (10 m length) is larger than E1 and E2 as well. For key K1 (closed), the jockey is adjusted to touch the wire at point J1, so that there is no deflection in the galvanometer. Now, the first battery (E1) is replaced by second battery (E2) for working by making K1 open and K2 closed. The galvanometer gives then null deflection at J2. The value of ‌

E1

E2

is ‌

a

b′

, where a= .......... .