JEE Main 25 Feb 2021 Shift 1 Solved Paper

The electric field in a region is given E=(‌

3

5

E0

∧

i

+‌

4

5

E0

∧

j

)‌

N

C

. The ratio of flux of reported field through the rectangular surface of area 0.2m2 (parallel to YZ-plane) to that of the surface of area 0.3m2 (parallel to XZ - plane) is a:b, where a=..........
[Here

∧

i

,

∧

j

and

∧

k

are unit vectors along X,Y and Z-axes, respectively]