A solid sphere of radius R gravitationally attracts a particle placed at 3 R from its centre with a force F_{1}. Now, a spherical cavity of radius (\frac{R}{2}) is made in the sphere (as shown in figure) and the force becomes F_{2}. The value of F_{1}: F_{2} is [25 Feb 2021 Shift 1]

JEE Main 25 Feb 2021 Shift 1 Solved Paper

Section: Physics

Question : 15 of 90

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A solid sphere of radius R gravitationally attracts a particle placed at 3R from its centre with a force F1. Now, a spherical cavity of radius (‌

) is made in the sphere (as shown in figure) and the force becomes F2. The value of F1:F2 is

[25 Feb 2021 Shift 1]

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